They are 2 and 140 because their LCM is 140 and their product is 280
It means write down three pairs of numbers that are relatively prime like 4 and 9, 5 and 6, 13 and 25
The long but fool-proof way is to find the complete prime factorisation of the number. Then group all the factors into pairs, rejecting any that cannot be paired. The product of the numbers that are left is the largest square factor.
you whole numbers that seven go in to
You need at least two numbers to find an LCM. And they need to be whole numbers, not fractions.
As a general principle, you can find the LCM of two numbers by dividing their product by their GCF. This one won't work. The product of any two numbers with 5 as a common factor would have to end in 5 or 0.
10 and 28
They are: 2 and 140
3 and 84.
10 and 12
20 x 21 = 420
19
xy = 147 x/y = 3 x = 21 y = 7
For the product to be zero, one of the numbers must be 0. So the question is to find the maximum sum for fifteen consecutive whole numbers, INCLUDING 0. This is clearly achived by the numbers 0 to 14 (inclusive), whose sum is 105.
find two positive numbers whose product is a maximum. 1.) the sum is s.
The numbers are 18 and 20.
asked to work out the product of two or more numbers, then you need to multiply the numbers together. If you are asked to find the sum of two or more numbers, then you need to add the numbers together.
you are a nerd