There is a trick to this one.
cube the first and write it down.
write the opposite sign of the middle term.
multiply the first constant times the second constant times 2 and write it down.
square the first term write it down, square the second term and write it down.
cube the last term including its sign and write it down.
Example:
(a-b)^3= a^3+2a^2b^2-b^3
(2x+3y)^3=8x^3=12x^2y^2+27y^3
(8m+6)
that;s so simple . try it
It depends on the product of sum of what.
(a + b)3 = a3 + 3a2b + 3ab2 + b3
The answer depends on the level of mathematics. With complex numbers, it is the squared magnitude of the binomial.
Consider a binomial (a+b). The cube of the binomial is given as =(a+b)3 =a3 + 3a2b + 3ab2 + b3.
99x99x99
To calculate the cube of a binomial, you can multiply the binomial with itself first (to get the square), then multiply the square with the original binomial (to get the cube). Since cubing a binomial is quite common, you can also use the formula: (a+b)3 = a3 + 3a2b + 3ab2 + b3 ... replacing "a" and "b" by the parts of your binomial, and doing the calculations (raising to the third power, for example).
jb+++u
(8m+6)
STEPS : FIRST TERM = the cube of the first term SECOND TERM=three times the product of the squareof first term and second term THIRD TERM=three times the product of first term and square of second term FOURTH TERM=THE CUBE OF THE LAST TERM ..
STEPS : FIRST TERM = the cube of the first term SECOND TERM=three times the product of the squareof first term and second term THIRD TERM=three times the product of first term and square of second term FOURTH TERM=THE CUBE OF THE LAST TERM ..
STEPS : FIRST TERM = the cube of the first term SECOND TERM=three times the product of the squareof first term and second term THIRD TERM=three times the product of first term and square of second term FOURTH TERM=THE CUBE OF THE LAST TERM ..
that;s so simple . try it
It depends on the product of sum of what.
56
...