That's it! You know everything there is to know about it. It's not as if you have to
wander through a crowd of vectors and find one that matches the description.
"Find the vector" means figure out its magnitude and direction. If the problem
already gave you the magnitude and direction, then it's unlikely that it's asking
you to 'find' that same vector.
The Resultant Vector minus the other vector
Use trigonometry.
The magnitude alone can't tell you anything about its components. You also need to know its direction.
Given a vector, speed is the magnitude of the velocity vector, |v|. Consider vector V= IVx + JVy + KVz the magnitude is |V| = ( Vx2 + Vy2 + Vz2)1/2
You can't derive the direction only from the magnitude. A vector with the same magnitude can have different directions. You need some additional information to make conclusions about the direction.You can't derive the direction only from the magnitude. A vector with the same magnitude can have different directions. You need some additional information to make conclusions about the direction.You can't derive the direction only from the magnitude. A vector with the same magnitude can have different directions. You need some additional information to make conclusions about the direction.You can't derive the direction only from the magnitude. A vector with the same magnitude can have different directions. You need some additional information to make conclusions about the direction.
Divide the vector by it's length (magnitude).
The Resultant Vector minus the other vector
Use trigonometry.
The magnitude alone can't tell you anything about its components. You also need to know its direction.
find the vector<1,1>+<4,-3>
By finding the direction of angular velocity because it's always parallel to it.
Given a vector, speed is the magnitude of the velocity vector, |v|. Consider vector V= IVx + JVy + KVz the magnitude is |V| = ( Vx2 + Vy2 + Vz2)1/2
You can't derive the direction only from the magnitude. A vector with the same magnitude can have different directions. You need some additional information to make conclusions about the direction.You can't derive the direction only from the magnitude. A vector with the same magnitude can have different directions. You need some additional information to make conclusions about the direction.You can't derive the direction only from the magnitude. A vector with the same magnitude can have different directions. You need some additional information to make conclusions about the direction.You can't derive the direction only from the magnitude. A vector with the same magnitude can have different directions. You need some additional information to make conclusions about the direction.
If they are parallel, you can add them algebraically to get a resultant vector. Then you can resolve the resultant vector to obtain the vector components.
7
Momentum = (mass) x (velocity vector).Given constant velocity, and assuming that mass doesn't change,there is no change in momentum over time.If there is any change in momentum, it can only be due to a change in mass.It would change in direct proportion to the mass, and the direction of themomentum vector would remain constant, in the direction of the velocity.
I suspect the question arises from confusion. A vector itself already defines a direction, usually in the Cartesian xyz coordinate system. If you want to express the direction in other coordinates, such as polar or spherical coordinates you need to transform the vector to these coordinate systems. I can answer you question more fully if you can specify the specific coordinate system in which you want to know the direction.