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The gradient of the tangent at that point, or if you know the equation of the line, the differential of the equation at that point..

This is similar but It is simpler:

Step 1 -- From the distance-time graph, if you know what time you are particularly in, go to your time axis (should be the horizontal axis) and from this particular time (point) on the time axis, go vertically upwards until it intersects the graph. Step 2 -- At this point of intersection, go horizontally to the left and read the value of the point at which this horizontal line intersects the vertical axis. This is the distance travelled by the body/particle at the particular instant chosen. Step 3 -- To determine the instantaneous velocity, simply divide the distance (determined in Step 2) by the time (from Step 1).

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9y ago
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12y ago

By calculating the slope at different or deisired points on the position-time graph by drawing tangents at the points. Since, slopes on a position-time graph represent velocity, you now have the velocity of the object at the time on which you have drawn the tangents. Now, that you have the velocity and you already had the time, all you have to is sketch the velocity-time graph

Remember

Slope (velocity on position-time graph)= 'd2-d1' divided by 't2-t1'

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11y ago

calculate distance from area under graph between equal time intervals

ie 0-1 secs , 1-2 secs

if v/t graph is mathematical curve, then use integration , if not then estimate.-1.286 - -1

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12y ago

By getting the displacements S1 at time t1 and S2 at time t2, now we use the expression S2 - S1 / t2 - t1. This gives the average velocity in the duration of time from t1 to t2.

Instantaneous velocity is got by finding the slope of the tangent drawn to the curve at that instant of time.

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13y ago

If time is the x-axis, and velocity is the y-axis, then find the specific time you want to know, then determine on the graph the velocity for that specific point in time, and that is the instantaneous velocity.

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Q: How can you obtain an average velocity and instantaneous velocity from a displacement-time graph?
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Continue Learning about Physics

What does a distance time graph allow you to find?

Besides obviously distance at any instant, on a connected, continuous distance-time graph, you can obtain instantaneous velocity and instantaneous acceleration.


How can you obtain the average velocity and instantaneous velocity from a displacement time graph?

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How can you obtain the average velocity and instantaneous velocity from a displacement - time graph?

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Related questions

What does a distance time graph allow you to find?

Besides obviously distance at any instant, on a connected, continuous distance-time graph, you can obtain instantaneous velocity and instantaneous acceleration.


How can you obtain the average velocity and instantaneous velocity from a displacement time graph?

To obtain the average velocity from a displacement-time graph, you can calculate the slope of the line connecting two points on the graph. Divide the change in displacement by the change in time. To obtain the instantaneous velocity, you need to find the slope of the tangent line at a specific point on the graph. Choose a point on the graph and draw a line tangent to the curve at that point. The slope of this tangent line will give you the instantaneous velocity at that specific point.


How would you obtain the acceleration of an object from a velocity time graph?

The average acceleration can be obtained by finding the slope of the graph. The instantaneous acceleration is found by drawing a tangent to a particular point on the graph (instant) and finding the slope of than tangent.


How can you obtain the average velocity and instantaneous velocity from a displacement -time graph?

You cannot because a displacement-time graph is concerned only with radial motion: displacement from a fixed point of reference. Any transverse motion is completely ignored. Thus, if you had a body going around in a circle about the point of reference, its speed would be recorded zero!


How can you obtain the average velocity and instantaneous velocity from a displacement - time graph?

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