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Q: How do you find prime factors fo a number?

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Its factors are itself and one because 37 is a prime number

1,2,4,5,10,20 2 and 5 are prime.

61 is already prime and is its own prime factor.

The prime factors of 56 are 2 and 7. For them to be common, they need to be compared to another set of prime factors.

As the product of its prime factors: 2*2*2*5*11 = 440 or as 23*5*11 = 440

Prime factors of 378: 2, 33 and 7 Prime factors of 360: 23, 32 and 5 LCM: 23*33*5*7 = 7560

Finding the prime factors of a number involves repeated division of the number by prime numbers and only moving on when that prime will not evenly divide into the number, until we end up with a quotient of 1. 48 ÷ 2 = 24 (we always start with 2, the lowest prime) 24 ÷ 2 = 12 12 ÷ 2 = 6 6 ÷ 2 = 3 (2 will not evenly divide into 3, so we move on to the next prime) 3 ÷ 3 = 1 So we divided by 2 four times and by 3 once.... so the prime factors fo 48 are 2, 2, 2, 2 and 3.

525 = 3 × 52 × 7

461 is a prime number and is only divisible by 1 and 461

Finding the prime factors of a number involves repeated division of the number by prime numbers and only moving on when that prime will not evenly divide into the number, until we end up with a quotient of 1. 48 ÷ 2 = 24 (we always start with 2, the lowest prime) 24 ÷ 2 = 12 12 ÷ 2 = 6 6 ÷ 2 = 3 (2 will not evenly divide into 3, so we move on to the next prime) 3 ÷ 3 = 1 So we divided by 2 four times and by 3 once.... so the prime factors fo 48 are 2, 2, 2, 2 and 3.

1,5,7,35

The factors of 65 are: 1, 5, 13, 65.

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