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The bounds of integration are 10 and 20. The function that we are integrating is Q(t)=4(.96t)=3.84t.

So the average value of Q(t) from 10 to 20 is equal to [1/(20-10)]*the integral from 10 to 20 of 3.84t dt.

Simplifying, we get .384*the integral from 10 to 20 of t dt.

Integrating, we get that the average value = .384(20^2 - 10^2)/2 = .196*(400 - 100) = .196 * 300 = 58.8.

The average value in question is exactly 58.8 grams.

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โˆ™ 2014-08-06 08:09:05
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Q: How do you find the average value of Q of t over the interval 10 less than or equal to x which is less than or equal to 20 and Q of t equals 4 times .96 t grams?
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