An equilateral triangle can be divided in half (along the height or altitude) into two right triangles (30° 60° 90°). The hypotenuse will be equal to one side. The two legs will be equal to the height and 1/2 of a side.
So height = side * (√3)/2, and side = height*2/(√3) = (height*2*√3) / 3
{Approx: 1.1547 * height}
No. 1/2 base squared + height squared=side squared on an equilateral triangle.
It is the height of the perpendicular line from its vertex to its base
It is: 0.5*base*perpendicular height
The base length is 5.2643 units and the height is 4.55902 units.
The area of a triangle is one-half the product of the triangle's base and height. The height of an equilateral triangle is the distance from one vertex along the perpendicular bisector line of the opposite side. This line divides the equilateral triangle into two right triangles, each with a hypotenuse of 9c and a base of (9/2)c. From the Pythagorean theorem, the height must be the square root of {(9c)2 - [(9/2)c]}, and this height is the same as that of the equilateral triangle.
An equilateral triangle with a height of 20 has a base of 23.1 (23.09401), not 15. If the base is 15 then the height will be 13 (12.99038).
No. 1/2 base squared + height squared=side squared on an equilateral triangle.
It is the height of the perpendicular line from its vertex to its base
Base x height x .50
It is: 0.5*base*perpendicular height
The base length is 5.2643 units and the height is 4.55902 units.
The area of a triangle is one-half the product of the triangle's base and height. The height of an equilateral triangle is the distance from one vertex along the perpendicular bisector line of the opposite side. This line divides the equilateral triangle into two right triangles, each with a hypotenuse of 9c and a base of (9/2)c. From the Pythagorean theorem, the height must be the square root of {(9c)2 - [(9/2)c]}, and this height is the same as that of the equilateral triangle.
You can't.You need either the area or the base when given the height in order to solve the 3rd parameter.Area = 1/2 Base x HeightorBase = 2*Area / Height.Additional Information:-Yes, whilst agreeing with the previous contributor's answer, nevertheless it's quite possible to find the base and area of a triangle given only its perpendicular height providing that is an equilateral triangle by means of trigonometry and Pythagoras' theorem.Agreed, my learned friend, but "equilateral" was not part of the question.
The formula to calculate the area of a triangle is (base/2) x height... therefore the are of the triangle in this case is 18 square inches
this works on equilateral where it would be base sqaured divided by two. otherwise you need another piece of information to solve which does not have to be height
Cutting the equilateral triangle in half results in two right triangles each with a base of length x/2, and angles of 30, 60, and 90 degrees. Using the lengths of sides of a 30-60-90 triangle it can be found that the height is (x/2)√(3), which is the same as the height of the equilateral triangle.So the height of the equilateral triangle is x√(3) / 2.
Area = 1/2*base*perpendicular height.