A diagonal bisecting a square creates two identical right triangles. The diagonal is the hypotenuse of a right triangles, so its length is the square root of the sums of the squares on the opposite two sides.
The area of rhombus with diagonals 28Cm square and 28Cm is: 392 cm2
It's not possible
The area is 32 cm2
They are at the end points of its diagonals
-- Draw both diagonals. -- They intersect (meet and cross) at the midpoint of the square.
A = 24.5 square feet.
The area of rhombus with diagonals 28Cm square and 28Cm is: 392 cm2
If both diagonals are 10 units then the rhombus is, in fact, a square. Its area is 50 square units.
A square has perpendicular diagonals. They are all the same angle (90 degrees). All sides are the same length. To find area of a square, use the formula A=4s. (Area=4xthe lenghth of the sides.)
It's not possible
Find the area of a rhombs with diagonals that measure 8 and 10.
The area is 32 cm2
60 square feet.
60 square units.
If those are its diagonals then area is: 0.5*10*11 = 55 square units other wise use Pythagoras to find diagonal EG because area of a rhombus is 0.5 times the product of its diagonals.
Area of a kite in square units = 0.5 times the product of its diagonals
They are at the end points of its diagonals