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if you have a right angle and the other called fe is 14ft

then what is fd?

Q: How do you find the height of a right angle isosles?

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Area = 1/2 b h b : base h : height The height is vertical side of the right angle; the base is the horizontal side of the right angle

You have to use trig. If the base angle is a and base b, the height is b tan(a).

i dont care about math even though i use it.

(base x height) / 2

Let the angle = θLet the height = aLet the base = b* means multiplied byIf the angle touches the base:tanθ = a/bb = a/tanθIf the angle touches the height:tanθ = b/ab = a*tanθWhen transferring the second line of working (b= ...) into a calculator, replace a with the height and θ with the angle. The answer will be b.

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right angle

Area = 1/2 b h b : base h : height The height is vertical side of the right angle; the base is the horizontal side of the right angle

You have to use trig. If the base angle is a and base b, the height is b tan(a).

K

Assuming you know the angle of ascension, and the base, you can calculate the height by recalling that tangent theta is height over base. Simple algebra from there: height is tangent theta times base.

the equation is 1/2 x base x height or (base x height)/2

i dont care about math even though i use it.

(base x height) / 2

Let the angle = θLet the height = aLet the base = b* means multiplied byIf the angle touches the base:tanθ = a/bb = a/tanθIf the angle touches the height:tanθ = b/ab = a*tanθWhen transferring the second line of working (b= ...) into a calculator, replace a with the height and θ with the angle. The answer will be b.

It is: perimeter minus hypotenus+base = height Area = 0.5*base*height

Providing it's a right angle triangle the formula is: hypotenuse2-base2 = height2

The general formula for a triangle is Base x Height / 2. That applies quite easily for a right angle triangle.