Measure them with a protractor
The exterior angles of any polygon add up to 360 degrees
The sum of the exterior angles of any polygon is 360 degrees.
The exterior angles of any polygon add up to 360 degrees.
The exterior angles of any polygon always add up to 360 degrees
Exterior angles of ANY polygon add to 360 degrees. Individual angles are therefore 360/n where n is the number if sides. 72
8 Since the sum of the exterior angles of any polygon is always 360, you can divide 360 by 45 to find the number of exterior angles, which is 8. That means 8 interior angles and eight sides as well.
Use a protractor
The exterior angles of any polygon add up to 360.
When a polygon is regular, each exterior angle is equal to the other exterior angles. Since the sum of all the exterior angles is 360 degrees, if you divide 360 by the measure of one exterior angle, you will get the number of sides. If you instead have the measure of an interior angle, simply calculate (180 - interior angle measure) to find the measure of the exterior angle, and use the above paragraph.
The sum total of all exterior angles of any polygon is 360 degrees. So if you're given thevalue of one exterior angle AND THE POLYGON IS REGULAR(all exterior angles are thesame size), all you have to do is divide the size of one angle into 360, and the quotientis the number of sides.
The sum of a regular polygons exterior angles always = 360
The answer will depend on what measure you are interested in: interior or exterior angles, lengths of sides, principal diagonals, apothem, area.
it always equals to 360
For any n-sided regular polygon the exterior angles are 360/n degrees.
I think its this.... Find the interior. Then do 180 - the interior. That is the exterior. * * * * * The correct answer is that the sum of the exterior angles of any polygon is always 360 degrees.
4140Improved Answer:-Exterior angles = 360 degreesInterior angles = 4140 degrees
Given a shape as such... ______________________________________ / A=72 B=65 \ \ / \_C=105__________________D=110_______/ (sorta) You take the interior angles that you have and subtract them from 360 to get their supplementary angles, which would be the measure of the outside angles corresponding to the interior angles Measure of <A= 72- so 360- 72=288*; so the measure of the exterior angle corresponding to <A is 288* You can do the same thing for the rest of the angles in the polygon. Hope it helps...
Divide one of its exterior angles into 360
Yes and here is why. The sum of the exterior angles of a regular polygon of n sides is 360°. Each exterior angle measures 360°/n. So we need to find a natural number n such that 360/n=30 and that n will be the number of angles in the polygon. 360/n=30 360=30n 360/30=n so n would need to be 12 and a 12 sided regular polygon has each exterior angle of measure 30 degrees.
The sum of the exterior angles of a 2D planar polygon is always 360 degrees.
A regular polygon has sides of equal length, as well as interior angles of equal measure. But for any regular polygon, the sum of the measures of the exterior angles is 360 degrees. You can use this information to find out the measure of an interior angle, because the sum of the measures of each interior/exterior pair of angles is always 180 degrees. So to find the answer to this problem, divide 360 by 7. Each exterior angle is about 51.4 degrees. Subtract that number from 180. Each interior angle is about 128.6 degrees.
Each exterior angle of a regular polygon with n sides has the angular measure of 360 degrees/(n - 2). A polygon has the same number of sides as angles, so that the total angular measure S of all the exterior angles will be 360 n/(n - 2); S(n - 2) = 360 n; nS - 2S = 360 n; n(S - 360) = 2S; n = (2S)/(S - 360).
If it's a regular polygon: 360/number of sides = each exterior angle
If it is a regular polygon then divide the exterior angle into 360 degrees to find the amount of sides it has because the exterior angles of any polygon add up to 360 degrees.