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How do you find the midpoint the slope the perpendicular slope and the equation for the perpendicular bisector of the line segment joining the points of 3 5 and 7 7?
Wiki User
∙ 13y ago
Midpoint = (3+7)/2, (5+7)/2 = (5, 6)
Slope of line segment = 7-5 divided by 7-3 = 2/4 = 1/2
Slope of the perpendicular = -2
Equation of the perpendicular bisector: y-y1 = m(x-x1)
y-6 =-2(x-5)
y = -2x+10+6
Equation of the perpendicular bisector is: y = -2x+16
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∙ 13y ago
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What is the perpendicular bisector equation joining the line segment of -2 plus 5 and -8 -3 giving brief details?
Points: (-2, 5) and (-8, -3) Midpoint: (-5, 1) Slope: 4/3 Perpendicular slope: -3/4 Use: y-1 = -3/4(x--5) Bisector equation: y = -3/4x-11/4 or as 3x+4y+11 = 0
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First find the midpoint of (-2, 5) and (-8, -3) which is (-5, 1) Then find the slope of (-2, 5) and (-8, -3) which is 4/3 Slope of the perpendicular bisector is the negative reciprocal of 4/3 which is -3/4 Now form an equation of the straight line with a slope of -3/4 passing through the point (-5, 1) using the formula y-y1 = m(x-x1) The equation works out as: 3x+4y+11 = 0
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