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A sector is the area of a circle defined by an angle from the center and the arc of the circle.

This area equals angle theta / 360 x pi x radius squared.

example: r=2 inches, theta = 60 degrees

then: 60/360 x 3.141592 x 2*2 = 1/6 x 3.141592 x 4 = 2.0944 sq. in.

I'm assuming by minor segment you mean the one defined by an angle less than 180 degrees. and that the remainder is the greater segment?

Q: How do you find the minor sector in a circle?

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If it is a sector of a circle then the arc is the curved part of the circle which forms a boundary of the sector.

That would certainly do it.

If you have the arc length:where:L is the arc length.R is the radius of the circle of which the sector is part.

Multiply ( pi R2 ) by [ (angle included in the sector) / 360 ].

Tell lachlan to kill himself...!

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If it is a sector of a circle then the arc is the curved part of the circle which forms a boundary of the sector.

Geometrically, the parts of a circle are the diameter, radius, chord(s), circumference, arc, sector, segment, tangent, secant, the minor sector, and the major sector.

Area of sector/Area of circle = Angle of sector/360o Area of sector = (Area of circle*Angle of sector)/360o

That would certainly do it.

For a circle where sector measures 10 degrees and the diameter of the circle is 12: Sector area = 3.142 square units.

If you have the arc length:where:L is the arc length.R is the radius of the circle of which the sector is part.

It depends on what information you have: the radius and the area of the sector or the length of the arc.

Multiply ( pi R2 ) by [ (angle included in the sector) / 360 ].

Multiply ( pi R2 ) by [ (angle included in the sector) / 360 ].

Tell lachlan to kill himself...!

area of sector = (angle at centre*area of circle)/360

If the sector of a circle has a central angle of 50 and an area of 605 cm2, the radius is: 37.24 cm