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How do you find the missing parts of an oblique triangle which 3 sides are given?
Wiki User
∙ 8y ago
Let the sides be x, y, z.
Let the angles opposite those sides be X, Y, Z
You can use the Cosine Law which states
cos X = (y^2 + z^2 - x^2)/2yz
Then calculate cos^-1(or arccos X) and this will give you the angle in degrees.
then do the same for Y
cos Y = (x^2 + z^2 - y^2)/2xz
Do the same to get Y.
Then add X and Y and subtract for 180° and you have your three angles.
Wiki User
∙ 8y ago
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nonononono
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