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Q: How do you find the multiplicative inverse of mixed numbers?

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Divide 1 by the number. The multiplicative inverse of 7 is 1/7, for example.

Swap the numerator and denominator. For example, the multiplicative inverse of 5/7 is 7/5

Using the extended Euclidean algorithm, find the multiplicative inverse of a) 1234 mod 4321

This may refer to the additive inverse, or to the multiplicative inverse. To find the additive opposite (negative) of a number multiply it by -1 The only number without an opposite is 0. To find the multiplicative inverse (reciprocal), make the number the numerator of a fraction (e.g., the reciprocal of 3 is 1/3). The additive inverse of 4 is minus 4 (the idea is to have two numbers that add up to zero), whereas the multiplicative inverse of 4 is 1/4 (the idea is to have two numbers whose product is 1).

The multiplicative inverse of a number is its reciprocal, meaning the multiplicative inverse of the rational number a/b is b/a. In the specialized case for integers, the multiplicative inverse of n is 1/n. This is due to the fact that a/b * b/a = 1 and n * 1/n = 1, which is the definition of a multiplicative inverse. More succinctly, to find the multiplicative inverse you "flip" the fraction or integer around to its reciprocal. This is the number that when multiplied with the original number results in a product of 1.

find the inverse of (1,-5)(3,-3)(4,-2)

The answer depends on what you mean by "opposite": whether it is the additive inverse or the multiplicative inverse.

7

9/5

Additive inverse: change all signs. Multiplicative inverse: flip it over.

I guess you mean a mixed fraction, such as 5 2/3, which basically means 5 + 2/3. To get the multiplicative inverse, you must first convert the fraction to an improper fraction (in this example, 17/3). Then, to get the multiplicative inverse, you exchange top and bottom (in this example, 3/17). Note that to do the conversion, I multiplied 5 x 3, and added 2 to the result. This number (17) goes into the numerator (top); the denominator (bottom) doesn't change.

To find the multiplicative inverse of a complex number z = (a + bi), divide its complex conjugate z* = (a - bi) by z* multiplied by z (and simplify): z = 4 + i z* = 4 - i multiplicative inverse of z: z* / (z*z) = (4 - i) / ((4 - i)(4 + i) = (4 - i) / (16 + 1) = (4- i) / 17 = 1/17 (4 - i)

Yes - after converting to an improper fraction, you flip it. Example: find the reciprocal (i.e., the multiplicative inverse) of 2 1/2 (two and a half). Reciprocal of (2 1/2) = reciprocal of (5/2) = 2/5.

change it to an improper fraction and then divide it

The definition of an multipilicative inverse is a number that's times by the known number to attain a product of one. To find the multiplicative inverse is the same thing as the recipricol of the number. To find the multiplicitive inverse or recipricol of a number, first turn the number into a fraction, then switch the numerator and denominator around. The result is your multiplicitive inverse.

To find the multiplicative inverse, you would have to solve the equation 0 times x = 1. Since any number times 0 is zero, this equation has no solution.

So if you have a number z = a + bi. Then how to find 1 divided by z. The way to figure this is to get the denominator as a pure real number. Multiplying the numerator and the denominator by the complex conjugate {a - bi} will result in a pure real denominator.(a - bi)(a + bi) = aÂ² + abi - abi - (bi)Â² = aÂ² + bÂ². So the multiplicative inverse is(a - bi)/(aÂ² + bÂ²)

You take its reciprocal, that is you divide 1 by the number. A rational number can be written as a fraction with integer values in both the numerator and denominator, j/k. The multiplicative inverse of a number is what you have to multiply by to get a product of 1. Putting these ideas together, the multiplicative inverse is the reciprocal, or k/j: (j/k) * (k/j) = 1.

Formally, a number n, has an inverse mod p only if p is prime. The inverse of n, mod p, is one of the numbers {0, 1, 2, ... , k-1} such that n*(p-1) = 1 mod p If p is not a prime then: if n is a factor of p then there is no such "inverse"; and if n is not a factor of p then there may be several possible "inverses".

Find the sum of two mixed numbers by applying the procedure for adding mixed numbers, Solve a real-world problem by subtracting mixed numbers.

just multiply.

The additive inverse of 6+4i is -6-4i since their sum is 0. It is analogous to real numbers where the additive inverse of 6 is -6 since 6+-6 =6-6=0 In the case of complex numbers, we add them by adding the real parts and then adding the imaginary parts. So to find the complex additive inverse of a+bi, we find the inverse of a which is -a and of bi which is -bi and so the additive inverse is -a-bi

you just flip the numbers to the denominator of a fraction

Change the mixed numbers to improper fractions, find a common denominator and proceed.

you can only find the perimeter of shapes, honey, not fractions.