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Each angle theta is (n-2)/n) x 180 degrees

The sum of all angles is nx theta = (n-2) x 180

sum = 180 n - 360

sum + 360 = 180 n

n = (sum + 360)/180 = sum/180 + 2

So you divide sum by 180 then add 2

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Q: How do you find the number of sides a polygon has with the sum of the interior angles?
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What is the sum of the interior angle measures of a polygon?

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It is: (n-2)*180 = sum of interior angles whereas 'n' is the number of sides of the polygon


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