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Each angle theta is (n-2)/n) x 180 degrees

The sum of all angles is nx theta = (n-2) x 180

sum = 180 n - 360

sum + 360 = 180 n

n = (sum + 360)/180 = sum/180 + 2

So you divide sum by 180 then add 2

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โˆ™ 2011-01-20 16:50:34
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Q: How do you find the number of sides a polygon has with the sum of the interior angles?
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Related questions

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What regular polygon has interior angle 177?

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What is the formula to find the sum of the interior angles of any polygon?

The sum of the interior angles (the angles of a polygon is equal to the 180*(n-2), where n is the number of sides. For example, if a polygon has 5 sides the sum of the angles is 180*(5-2), which is 540 degrees.


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What is the sum of the interior angles of the polygon?

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