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To find the prime factors of a number, divide the number by the smallest Prime number as many times as needed, then by the next smallest prime, forming a "factor tree."

180 / 2 = 90
90 / 2 = 45
45 / 3 = 15
15 / 3 = 5

The prime factors are 2 x 2 x 3 x 3 x 5 or 22 x 32 x 5

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11y ago
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11y ago

Divide 180 by 2 until you hit 45. Divide 45 by three until you hit 5. Write them down.

2 x 2 x 3 x 3 x 5 = 180

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Q: How do you find the prime factors of 180?
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What are prime factors of 180?

The prime factors are: 2,3,5


Is 7 a prime factor of 180?

No. The Prime Factors of 180 are: 2, 3, 5.


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The prime factors of 180 are 2, 3, and 5 .


Is the prime factorization of 180?

As a product of its prime factors: 2*2*3*3*5 = 180


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prime factors of 180:(180) = 2 * (90)(90) = 2 * (45)(45) = 3 * (15)(15) = 3 * 5prime factors of 180 are: 2*2*3*3*5


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Since they don't share any prime factors, multiply them. The LCM is 180.


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As a product of its prime factors in exponents: 22*32*5 = 180 So 5 is its largest prime factor.


What are all the prime factors of 180?

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What multiplies to get 180?

As a product of its prime factors: 2*2*3*3*5 = 180


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