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Given:

x2 + y2 - 10x + 4y + 4 = 0

First, we'll move our constants to the right:

x2 + y2 - 10x + 4y = -4

Then group terms with the same variables together:

x2 - 10x + y2 + 4y = -4

Then complete the squares:

x2 - 10x + 25 + y2 + 4y + 4 = -4 + 25 + 4

(x - 5)2 + (y + 2)2 = 25

And there we have it. This is an equation for a circle whose center point is at (5, -2), with a radius of √25, which equals 5.

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Q: How do you find the radius of the circle with the given equation of x2 plus y2-10x plus 4y plus 4 equals 0?
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