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Add the digits together. The sum of the digits of 23 is 5.

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Add the digits together. The sum of the digits of 23 is 5.

the sum of individual digits of a given integer number

The no. is 35.

int n; // we want to find the sum of digits of n int sum = 0; while(n != 0 ) { sum += n % 10; n /= 10; }

By the sum of its digits: 10. By each of its individual digits: 11.

28

192

45

100000 2847239582

There are many shell programs that will find the sum of the square of individual digits of a number. A small example is: SD=3n=2, sum=2, and SD=2.

if the sum of the cubic value of each digit of a number is equal to the original number , then that particular number is an Armstrong number :-) Actually, Armstrong numbers are the sum of their own digits to the power of the number of digits.

the sum of my digits is 6? answer=60

26

The number is 23.

34.

int Sum( int digits ) { if(digits < 10) return digits; return digits%10 + Sum(digits/10); }

The number is 45. The sum of its digits i.e. 4+5=9 Five times the sum of its digits i.e. 5 times 9 which is 45

You would fill in the blank with the word sum, which means that you add each of the digits of the number. If that sum is divisible by three then the number is divisible by 3.

A krishnamurthy number is one whose sum of the factorials of each number is equal to the number itself. Example145sum of factorial of each digits = 1+24+120 = 145 which is the number itself.

3201

45

8 is the same as the sum of the digits of its cube, 512.

1 + 1 = 2 The sum of the digits is therefore 2.

The sum of your digits is the total number arrived at after adding two or more numbers.

no thanks