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Q: How do you find the time given only distance initial velocity and final velocity?

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Distance = |(v2 - u2)/(2a)| where initial velocity = u final velocity = v accelaration = s

Without distance, you have to know time, initial velocity, and acceleration, in order to find final velocity.

v = 2s/t - u where u=initial velocity, v=final velocity, s = distance and t = time

One formula that can be used - assuming constant acceleration, of course! - is vf2 = vi2 + 2as, where vf is the final speed, vi is the initial speed, a is the acceleration and s is the distance. In your case, solve for final velocity.

Average speed = 1/2 (initial speed + final speed) Time = (distance)/(average speed)

v2 - u2 = 2as so that a = (v2 - u2)/2s where u = initial velocity v = final velocity s = distance a = acceleration

You can't. You need either the final velocity or the acceleration of the object as well, and then you can substitute the known values into a kinematics equation to get the initial velocity.

since time is given you are done

You cannot.

V= vi + at

If you know the initial and final velocity you can determine the acceleration (Velocity final- Velocity initial)/time = acceleration This can also be seen by integrating the acceleration. In this case lets assume acceleration is constant, then: acceleration=C Integration from time=initial to time=final gives C*(time final-time initial)=velocity final-velocity initial This integration scheme can also work if acceleration is not constant. In this case you must know how acceleration or velocity changes with time.

If you take initial velocity(Vi) to be zero and the final velocity (Vo) to be a known. Puting the knowns into a triganonomical equation and solving for the value of D would give an answer

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