The answer will depend on what c is!
If the trinomial is ax^2 + bx + c then the required value of c is (b^2)/(4a)
-12
(b/2)^2= 64
There are infinitely many possible answers: c = ±4x + 33
49
49
What value, in place of the question mark, makes the polynomial below a perfect square trinomial?x2 + 12x+ ?
81.
64
-12
144
(b/2)^2= 64
48
There are infinitely many possible answers: c = ±4x + 33
x2 + 22x + 121 to get this divide 22 by 2... then square the answer you get from that 22/2 = 11 112 = 121
-26
I'm going to go out on a limb and assume that y2 8y c actually means y^2 + 8y + c c = 16 makes a perfect square: (y + 4)^2 = (y+4)*(y+4) = y^2 + 8y + 16
6.25