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Q: How do you find the value of variables in angles of a polygon when subtract and add?

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A polygon can have any kind of angles: acute, right, obtuse and reflex. An angle can have any value in the range (0, 360) degrees excluding 180 degrees.

Restate the question: how do you find the number of sides in a regular polygon if you know the measure of an interior angle? (If this is not your question, please resubmit the question with different wording.) Subtract the interior angle from 180 deg - for example 180-160 = 20. Now divide 360 by this value: 360/20 = 18. A regular polygon with interior angles of 160 degrees has 18 sides.

Any value between 0 and 360 degrees (not including those two values). If the polygon were regular, and that is a BIG if, then each interior angle would be 108 degrees.

I'm guessing you mean with parallels and a transversal. If this is the case, then find he angle that is either a; supplementary (creating a flat angle, 180 degrees) or b; complimentary (creating a 90 degree angle) subtract the supplementary/complimentary angle from either 180 or 90 and the difference is your answer. Hope I helped! * * * * * More likely the question is concerned with the interior angles of a polygon. If the polygon is irregular then there is no simple answer. An interior angle can have any value. However, if it is a regular polygon then the question can be answered. The sum of all the exterior angles is 360 degrees - irrespective of the number of sides (or vertices). Suppose the polygon has n sides/vertices. Then, since it is regular, each exterior angle is 360/n. Therefore, each interior angle is 180-360/n degrees.

You could measure it using a protractor, derive it from basic geometric properties (for example angles of a regular polygon), or calculate it using trigonometry.

Related questions

A regular polygon is a polygon whose sides are equal length and whose angles are all the same value. A non regular polygon is just the opposite of a regular polygon.

Equate the coefficients and subtract or add to find the value of the the given unknown variables.

A polygon can have any kind of angles: acute, right, obtuse and reflex. An angle can have any value in the range (0, 360) degrees excluding 180 degrees.

The exterior angles of any polygon including a 36 sided polygon always add up to 360 degrees.

Restate the question: how do you find the number of sides in a regular polygon if you know the measure of an interior angle? (If this is not your question, please resubmit the question with different wording.) Subtract the interior angle from 180 deg - for example 180-160 = 20. Now divide 360 by this value: 360/20 = 18. A regular polygon with interior angles of 160 degrees has 18 sides.

Find the two varying exterior angles. For example, if they are alternating 120 degrees and 150 degrees, the external angles must be 60 degrees and 30 degrees. Since the sum of external angles for every polygon is 360, you can add 30 and 60 (the two varying external angles) = 90 degrees, then divide 360 by 90 and multiply by 2.

Any value between 0 and 360 degrees (not including those two values). If the polygon were regular, and that is a BIG if, then each interior angle would be 108 degrees.

I'm guessing you mean with parallels and a transversal. If this is the case, then find he angle that is either a; supplementary (creating a flat angle, 180 degrees) or b; complimentary (creating a 90 degree angle) subtract the supplementary/complimentary angle from either 180 or 90 and the difference is your answer. Hope I helped! * * * * * More likely the question is concerned with the interior angles of a polygon. If the polygon is irregular then there is no simple answer. An interior angle can have any value. However, if it is a regular polygon then the question can be answered. The sum of all the exterior angles is 360 degrees - irrespective of the number of sides (or vertices). Suppose the polygon has n sides/vertices. Then, since it is regular, each exterior angle is 360/n. Therefore, each interior angle is 180-360/n degrees.

The sum of the interior angles of a polygon with n sides is (n-2)*180 degrees. So, with n = 13, the sum of the interior angles is 11*180 = 1980 degrees. However, any particular interior angle can have any value between 0 and 360 degrees, (not inclusive of those limits). It is only in the case of a REGULAR polygon that the value of the interior angle can be determined without additional information. So, if the 13-polygon is regular, then each interior angles is 1980/13 = 1524/13 or 152.3077 degrees.

You could measure it using a protractor, derive it from basic geometric properties (for example angles of a regular polygon), or calculate it using trigonometry.

There are two formulae which can be used for this: 1: As the exterior angles of a regular n-sided polygon are 360/n degrees, the interior angle is 180 less this value; 2: The total of the interior angles of any n-sided polygon is (2n - 4) right angles so in a regular polygon each angle is that value divided by n. In your example n = 10, so by method 1 exterior angles are 36 degrees making the interior angles therefore 144 degrees; By method 2 the total of the interior angles is 16 x 90 ie 1440 degrees, making each angle 1440/10 ie 144 degrees!

It is not. The sum of all the interior angles is related to the number of sides but, unless the polygon is regular, each interior angles can have any value in the range (0, 360) degrees - the traingle being an exception where the maximum angle must be less than 180 degrees. There is nothing in the question that suggests that the polygon is regular and since only a minority of polygons are regular, you may not assume that it is a regular polygon.