0
If you know the equation, you just plug in x = 0 and solve.
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How do you find y and x intercept of parabola?
For the equation of any graph. The graph intercepts the y-axis, when x is zero, so in the equation, substitute x=0, and solve for y. To find the x-intercept, this is when y is zero, so substitute y=0, and solve for x. For a parabola, if the highest power of y is the 1st power (no exponent) and the highest power of x is 2, then the parabola opens up or down. The parabola will have 1 y-intercept (usually it is the constant value), and depending on where it is (if it is at the origin, it is also an x-intercept, and the other x-intercept has the same distance as y-intercept has from the axis of symmetry i.e y = a2x + bx), either have 2 x-intercepts, or no interceptions with the x-axis (i.e. y = x2 + c, c ≥ 0 or y = -x2 + c, c ≤ 0). If the highest power of y is 2, and highest power of x is 1, then it opens left or right, and it may have none or 2 y-intercepts, and will have 1 x-intercept. So when you're solving for the one that's a quadratic, if you come up with imaginary or complex roots, that means there is no intercept.
To find the value of a in a parabola opening up or down subtract the y-value of the parabola at the vertex from the y-value of the point on the parabola that is one unit to the of the vertex?
To find the value of a in a parabola opening up or down subtract the y-value of the parabola at the vertex from the y-value of the point on the parabola that is one unit to the right of the vertex.
How do you find the x and y intercepts of an equation?
Substitute zero for x to find the y-intercept, and substitute zero for y to find the x-intercept.
How do you find the x-intercept and the y-intercept of a graph?
X axis is across and Y axis is down
How do you find out the standard form when given the x and y intercept x-intercept -2 y-intercept 6?
-8
How do you find the y intercept when given a parabola in standard form?
At any point on the y-axis, the x-coordinate is zero. In the equation of the parabola, set x=0. Tidy it up, and you have " Y = the y-intercept ".
Is the y intercept a vertical line through the vertex of a parabola?
No.
When would not having a parabola x- intercept happen?
Consider a parabola described by the expression y = ax2 + bx + c first, calculate it's first and second derivatives: y' = 2ax + b y'' = 2a Find x value at which y' = 0, and calculate whether the corresponding y-coordinate is above or below the x-axis. If it's above the x-axis, then the parabola will not intercept the x-axis if y'' is greater than 0. If it's below the x-axis, then the parabola will not intercept the x-axis if y'' is less than 0. Otherwise, it will always intercept the x axis at two locations.
How do you find y and x intercept of parabola?
For the equation of any graph. The graph intercepts the y-axis, when x is zero, so in the equation, substitute x=0, and solve for y. To find the x-intercept, this is when y is zero, so substitute y=0, and solve for x. For a parabola, if the highest power of y is the 1st power (no exponent) and the highest power of x is 2, then the parabola opens up or down. The parabola will have 1 y-intercept (usually it is the constant value), and depending on where it is (if it is at the origin, it is also an x-intercept, and the other x-intercept has the same distance as y-intercept has from the axis of symmetry i.e y = a2x + bx), either have 2 x-intercepts, or no interceptions with the x-axis (i.e. y = x2 + c, c ≥ 0 or y = -x2 + c, c ≤ 0). If the highest power of y is 2, and highest power of x is 1, then it opens left or right, and it may have none or 2 y-intercepts, and will have 1 x-intercept. So when you're solving for the one that's a quadratic, if you come up with imaginary or complex roots, that means there is no intercept.
Does a parabola have to have an x-intercept?
No, a parabola does not have to have an x-intercept. ex. -2(x-2)^2 - 4 is a parabola that has no x-intercept.
How do you find the coordinants of a y-intercept and x-intercept?
To solve for intercepts on a straight line graph put the equation in the form y=mx+c where c is the y-intercept and you have the y intercept. Now to solve x-intercept set y=0 eg y=2x+5 0=2x+5 2x=-5 x=-2.5 For intercepts on other forms of graphs eg parabola y-intercept= make x equal to 0 and solve x-intercept= make y equal to 0 and solve
To find the value of a in a parabola opening up or down subtract the y-value of the parabola at the vertex from the y-value of the point on the parabola that is one unit to the of the vertex?
To find the value of a in a parabola opening up or down subtract the y-value of the parabola at the vertex from the y-value of the point on the parabola that is one unit to the right of the vertex.
How do you find x intercept and the meaning and y intercept?
solve the x and you find the y
What is the definition of graph intercept?
The intercept of a graph is the point where is crosses one of the coordinate axes. The x intercept is where it crosses the x axis, the y intercept where it crosses the y axis. If the graph is given as y equals a function of x, it is usually easier to find the y intercept, because that is where x is 0. You just plug in 0 for x and evaluate. To find the x intercept, you plug in 0 for y and then you have to solve an equation for x. This is fairly easy if it is a linear equation (the graph is a straight line), somewhat harder for a quadratic (a parabola). But anyway you only asked for a definition, and I have given it.
What is the general shape of a graph of a quadratic function in the form yax2 c?
y = ax2 + c is a parabola, c is the y intercept of the parabola. It also happens to be the max/min of the function depending if a is positive or negative.
What is y intercept and x intercept of y x plus 8?
To find the y intercept put zero in for x and solve. To find the x intercept put zero in for y and solve. (0,8) and (-8,0)
How do you find the y-intercept and x-intercept of y equals -1?
The function y = -1 has no x-intercept; its graph is a horizontal line with a y-intercept of -1.
