By figuring out the rule on which the sequence is based. I am pretty sure the last number is supposed to be 125 - in that case, this is the sequence of cubic numbers: 13, 23, 33, etc.
an = 4n - 14 So a35 = 35*4 - 14 = 140 - 14 = 126
65.......but there is a slight problem. The sequence appears to be a(n) = n3 + 1 apart from the first term which should be 2 as 13 + 1 = 2 1 23 + 1 = 9 33 + 1 = 28 43 + 1 = 65.....the missing number 53 + 1 = 126 63 + 1 = 217
4/7
63/52To reduce to lowest term:1. Get the GCF of 126 and 104126 = 2 * 3 * 3 * 7104 = 2...............* 2 * 2 * 13=================GCF =22. Divide 126 & 104 by their GCF.126 ÷ 2 = 63104 ÷ 2 = 52thus; lowest term is 63/52.
151
an = 4n - 14 So a35 = 35*4 - 14 = 140 - 14 = 126
Any number that you wish.
65.......but there is a slight problem. The sequence appears to be a(n) = n3 + 1 apart from the first term which should be 2 as 13 + 1 = 2 1 23 + 1 = 9 33 + 1 = 28 43 + 1 = 65.....the missing number 53 + 1 = 126 63 + 1 = 217
126/2394 = 1/19 by dividing by 126
90/126 is 5/7 in its lowest terms
They are 14, 42, 126, 378 and 1134.
1 3 6 18 36
4/7
63/52To reduce to lowest term:1. Get the GCF of 126 and 104126 = 2 * 3 * 3 * 7104 = 2...............* 2 * 2 * 13=================GCF =22. Divide 126 & 104 by their GCF.126 ÷ 2 = 63104 ÷ 2 = 52thus; lowest term is 63/52.
The "sixth square root" is an ambiguous term. The "sixth root" of 126 ... the number which when multiplied by itself 6 times becomes 126 ... is 2.23904 (rounded)
63/25
151