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How do you form an equation for the perpendicular bisector of the line segment joining the points of p q and 7p 3q showing all details of your work?
Wiki User
∙ 13y ago
First find the midpoint the slope and the perpendicular slope of the points of (p, q) and (7p, 3q)
Midpoint = (7p+p)/2 and (3q+q)/2 = (4p, 2q)
Slope = (3q-q)/(7p-p) = 2q/6p = q/3p
Slope of the perpendicular is the negative reciprocal of q/3p which is -3p/q
From the above information form an equation for the perpendicular bisector using the straight line formula of y-y1 = m(x-x1)
y-2q = -3p/q(x-4p)
y-2q = -3px/q+12p2/q
y = -3px/q+12p2/q+2q
Multiply all terms by q and the perpendicular bisector equation can then be expressed in the form of:-
3px+qy-12p2-2q2 = 0
Wiki User
∙ 13y ago
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