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Yyou could do (2x2)! (=24) then / 2 (= 12) then - 2/2 (= 11)
(where ! means factorial, so 4! means 4x3x2x1, = 24)
Is that allowed?
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∙ 14y ago
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Can you make 11 using only four 2s?
Yes: 2 x 2 x 2 + 2!
How do you get 11 with five 2s?
(2x2x2)/2 + 2
What is the answer to 2s plus 16 equals 4s - 6?
2s + 16 = 4s - 6 Subtract 2s from both sides: 16 = 2s - 6 Add 6 to both sides: 22 = 2s divide both sides by 2: s = 11
Can you make 9 using only four 2s?
Yes
How many 2s are in 42?
42 can be divided by 2 once. The result, 21, is not divisible by 2.
Can you make 11 using only four 2s?
Yes: 2 x 2 x 2 + 2!
If p equals 2s plus 5 what is s in terms of p?
If p = 2s + 5, then s = (p-5)/2 or 1/2 (p-5) --- p = 2s +5 p-5 = 2s (p-5)/2 = s
How can you make 2s equal 5?
If 2s = 5 then s = 2.5. So by letting s equal 2.5 (two and one half) you will allow 2s to equal 5.
How can you calculate 12 and 24 without using 2?
12 = 11+1 24 = 17 + 7 No 2s used in the calculations
How do you factor 4s2-9?
4s2 - 9 can be expressed by using the identity: a2 - b2 = (a-b)(a+b) Therefore, 4s2 - 9 = (2s)2 - 32 = (2s-3)(2s+3)
How do you simplify 7-2s plus 4 plus 5s?
7-2s+4+5s ..... Okay first you combine like terms(add the like terms)..so its going to be 11+3s I did 7+4=11 then -2s+5s=3s So the answer can be 11+3s or 3s+11
Is it possible to get 10 using 3 2s?
no.
2r plus 2s equals 50 and 2r minus s equals 17?
2r + 2s = 50 2r - s = 17 therefore 4r - 2s = 34 Add so that you can eliminate one of the variables: 2r + 2s = 50 4r - 2s = 34 ---------------- 6r + 0s = 84 Solve for r: 6r = 84 r = 14 Substitute r into one of the original equations: 2(14) + 2s = 50 28 + 2s = 50 2s = 22 s = 11 Doublecheck with the other original equation: 2(14) - 11 = 28 - 11 = 17
How do you get 11 with five 2s?
(2x2x2)/2 + 2
What is the answer to 2s plus 16 equals 4s - 6?
2s + 16 = 4s - 6 Subtract 2s from both sides: 16 = 2s - 6 Add 6 to both sides: 22 = 2s divide both sides by 2: s = 11
Factor the poynomial twice first use a common factor with a positive coefficient and then use a common factor with a negative coefficient -2s4 4s3-10s?
2s(-s^3 + 2s^2 - 5) -2s(s^3 - 2s^2 + 5)
Using exactly two 2s and any of the standard mathematical symbols write down an expression whose value is 5?
square root of 0.2^-2=5
