You can use three 2s to make 26 as follows (2x2)! + 2 = 26 So you can simply make 26 with five 2s as (2x2!) + 2 - 2 + 2 = 26
22 + 22 - 2 = 42
Not sure about five, but you can make 42 with 6 2s with this method: 2[(22)! - (2/2) - 2] = 42
(2x2x2)/2 + 2
Yes
You can use three 2s to make 26 as follows (2x2)! + 2 = 26 So you can simply make 26 with five 2s as (2x2!) + 2 - 2 + 2 = 26
22 + 22 - 2 = 42
26
Not sure about five, but you can make 42 with 6 2s with this method: 2[(22)! - (2/2) - 2] = 42
(2x2x2)/2 + 2
4s2 - 9 can be expressed by using the identity: a2 - b2 = (a-b)(a+b) Therefore, 4s2 - 9 = (2s)2 - 32 = (2s-3)(2s+3)
no.
Yes
2 + 2 + 2 + 2/2 = 6 - 1 = 5
2x2x2+2/2 = 9
you dont.
4194304 = 222