4! + 2*[sq(1) + sq(3)] = 24 + 2*(1 + 9) = 24 + 2*10 = 24+20 = 44
1, 2, 4, 11, 22, 44.
1, 2, 4, 11, 22, 44.
They are the numbers divisible by 2 with a remainder of 1
88
1, 2, 4, 8, 11, 22, 44, 88
44 is divisible by 1, 2, 4, 11, 22, 44.
1 and 44 2 and 22 4 and 11
1, 2, 4, 11, 22, 44.
1, 2, 4, 11, 22, 44.
1, 2, 4, 11, 22, 44.
1, 2, 4, 11, 22, 44.
1, 2 and 4
They are the numbers divisible by 2 with a remainder of 1
To find this, you first need to break 44 down into its prime factors. From times tables, we know that 44 = 11x4, and 4 can be broken down into 2x2. Thus the prime factors of 44 are 2, 2 and 11. The factors will be any combination of these numbers. Thus the factors of 44 are 1, 2, 4, 11, 22 and 44. Therefore there are a number of 3 number combinations that multiply to make 44. These are: 1, 1, 44 1, 2, 22, 1, 4, 11 2, 2, 11
Factors are numbers you can multiply together to get another number. 44: 1, 2, 4, 11, 22, 44
44 and 1 22 and 2 11 and 4
88