It could be: 4+40+40 = 6
(4/4)*4!/4 = 6
(4+4)/4 + 4 = 6 break-down: (4 + 4)/4 = 8/4 = 2 2 + 4 = 6
((6/3)+6)3
By using: (3*6)+(3*2) = 24
(44 - 4)/4 x 4/4
(4/4)*4!/4 = 6
(4+4)/4 + 4 =6
(4+4)/4 + 4 = 6 break-down: (4 + 4)/4 = 8/4 = 2 2 + 4 = 6
((6/3)+6)3
By using: (3*6)+(3*2) = 24
(44 - 4)/4 x 4/4
(4x4)-(4+4sqr) (4x4)=16 (4+4sqr)=6 16-6=10
All you have to do is find the number that appears the most. The mode for 2 3 4 6 6 and 9 would be six because there are two sixes. There is only one 2 3 4 5 and 9. If you had the numbers 2 4 4 6 6 6 8, the mode would be 6. There are three sixes and only two fours. The same goes for any set of numbers. If there are three fours and three sixes, there would be two modes-4 and 6. Hope this helped!
There are six fours in twenty-four.
9*6/3 + 6 = 9*2 + 6 = 18 + 6 = 24
9*9/3 + 6 - 2 = 9*3 + 6 - 2 = 27 + 6 - 2 = 31
no