Suppose thye original amount is y and the rate of interest is r%.
Then the total value after two years is y*(1+r/100)2 = y*(1 + r/50 + r2/10000)
So the compound interest, alone, after 2 years is y*(r/50 + r2/10000)
So y = compound interest/(r/50 + r2/10000)
Semiannually over two years is equivalent to 4 periods. If the interest is 12% every 6 months, then the amount of interest is It is 8000*[(1.12)4 -1] =4588.15
In 2.54 years the compound interest will amount to 282.39 in both cases.
Rs 1600.
Approximately 7 years. The general rule is to divide 70 by the interest rate to get an approximation of how long it will take to double. If the interest is compounded annual you will have $194.88 after 7 years, and $214.37 after 8 years. Though if interest is compounded more regularly (ie. monthly or daily) this will grow at a slightly faster rate.
10000 x (1.08)2 = 11664
That depends - on whether the interest is compound - or just on the original loan.
Interest alone would be 4.871463646 times the amount of the principle.
$44,440.71
If the rate of annual interest is r% the period is n years and the amount invested is y Then the compound interest is y*(1+r/100)^n - y
Compound Interest FormulaP = principal amount (the initial amount you borrow or deposit)r = annual rate of interest (as a decimal)t = number of years the amount is deposited or borrowed for.A = amount of money accumulated after n years, including interest.n = number of times the interest is compounded per yearExample:An amount of $1,500.00 is deposited in a bank paying an annual interest rate of 4.3%, compounded quarterly. What is the balance after 6 years?Solution:Using the compound interest formula, we have thatP = 1500, r = 4.3/100 = 0.043, n = 4, t = 6. Therefore, So, the balance after 6 years is approximately $1,938.84.
Compound interest functions can be represented as [(1+i)^t]*n, where i = interest rate t = time n = original number [(1.05)^5]*1500 = $1914.42
3
It depends on whether it is simple or compound interest. The formula for simple interest is A = P(1+rt), where A = amount of money after t years, P = Principal, or the amount of money you started with, and r = the annual interest rate, expressed as a decimal (i.e. 7% = 0.07). For compound interest, the formula is A = P(1+r)t.
There are two types of interest, simple and compound: Simple Interest is calculated by p*r*t where, p = principal (original amount invested) r = interest rate for one period t = time Compound Interest is calculated by p * (1+ (r/n)) ^ n*t where, p = principal r = interest rate n = number of times per year the interest is compounded t = number of years invested
That would depend on the original principal (the amount you borrowed) and how they compute interest.
Suppose the amount invested (or borrowed) is K, Suppose the rate of interest is R% annually, Suppose the amount accrues interest for Y years. Then the interest I is 100*K[(1 + R/100)^Y - 1]
Compound Interest for n compounds per year:A = P(1+r/n)ntWhereA = amount of money at time tP = Principal balancer = yearly interest raten = number of compunds per yeart = time in yearsContinuous Compound Interest:A = PertA = amount of money at time tP = Principal balancer = yearly interest ratet = time in years