you would need a calculator with an "integer divide" button
the TI-15 has one
By the time you advance to the point of dividing decimals, you don't use remainders any more.
With the divisor (the number you are dividing by) as 9, there are 9 possible remainders: 0, 1, 2, 3, 4, 5, 6, 7, and 8.
the max remainder you can have when dividing by a number is that number minus 1 So 4 can only have 1, 2 and 3 as remainders. 9 can only have 1-8 and so on.
Do it multiple times, and check it with a calculator multiple times also
Dividing 360 by:2=1803=1204=905=729=40So the answer is yes.
By dividing it by the prime factors that have no remainders
There are 11 possible remainders (1 to 11). If something is divisible by 12, there is said to be no remainder, but this can be considered to be a remainder of 0, making 12 possible remainders.
Try dividing it with a calculator. If you get numbers after the decimal point, it is NOT divisible.Try dividing it with a calculator. If you get numbers after the decimal point, it is NOT divisible.Try dividing it with a calculator. If you get numbers after the decimal point, it is NOT divisible.Try dividing it with a calculator. If you get numbers after the decimal point, it is NOT divisible.
1 & 2 are the only non-zero remainders you can get from dividing a whole number by 3.
By the time you advance to the point of dividing decimals, you don't use remainders any more.
Yes, there are, if you're dividing by a number that's over 11.
With the divisor (the number you are dividing by) as 9, there are 9 possible remainders: 0, 1, 2, 3, 4, 5, 6, 7, and 8.
All remainders on a calculator will appear as a decimal. Some TI scientific calculators can convert the answer into a fraction.
There are two possible nonzero remainders when dividing a number by 3: 1 and 2. Any nonzero integer can be divided by 3 resulting in either a remainder of 1 or 2.
Use a calculator!
Any non-negative integer less than the number that you are dividing by.
the max remainder you can have when dividing by a number is that number minus 1 So 4 can only have 1, 2 and 3 as remainders. 9 can only have 1-8 and so on.