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Aylin Schulist

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3y ago
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14y ago

Note: The square root of a negative number is a so-called imaginary number. This has no solution in the "real numbers". The imaginary unit, i, is equal to the square root of -1; so i2 = -1.

6 / root(-10)

= 6 / root(10) i

= 6i / root(10) x i2

= 6i / root(10) x (-1)

= 6i root(10) / -10

= 3i root(10) / -5

= (-3 root(10) / 5) i

Note: The square root of a negative number is a so-called imaginary number. This has no solution in the "real numbers". The imaginary unit, i, is equal to the square root of -1; so i2 = -1.

6 / root(-10)

= 6 / root(10) i

= 6i / root(10) x i2

= 6i / root(10) x (-1)

= 6i root(10) / -10

= 3i root(10) / -5

= (-3 root(10) / 5) i

Note: The square root of a negative number is a so-called imaginary number. This has no solution in the "real numbers". The imaginary unit, i, is equal to the square root of -1; so i2 = -1.

6 / root(-10)

= 6 / root(10) i

= 6i / root(10) x i2

= 6i / root(10) x (-1)

= 6i root(10) / -10

= 3i root(10) / -5

= (-3 root(10) / 5) i

Note: The square root of a negative number is a so-called imaginary number. This has no solution in the "real numbers". The imaginary unit, i, is equal to the square root of -1; so i2 = -1.

6 / root(-10)

= 6 / root(10) i

= 6i / root(10) x i2

= 6i / root(10) x (-1)

= 6i root(10) / -10

= 3i root(10) / -5

= (-3 root(10) / 5) i

This answer is:
User Avatar

User Avatar

Wiki User

14y ago

Note: The square root of a negative number is a so-called imaginary number. This has no solution in the "real numbers". The imaginary unit, i, is equal to the square root of -1; so i2 = -1.

6 / root(-10)

= 6 / root(10) i

= 6i / root(10) x i2

= 6i / root(10) x (-1)

= 6i root(10) / -10

= 3i root(10) / -5

= (-3 root(10) / 5) i

This answer is:
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Q: How do you get the solution to 6 divided by the square root of -10?
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