To get that type of expression into one with positive exponent, use this form:
a-n = 1/(aⁿ) where a is nonzero.
Then, y-10 = 1/(y10) by the form we use!
Suppose x and y are two POSITIVE numbers so that -x and -y are negative. Then a negative minus a negative = (-x) - (-y) = -x +y If x > y the answer is negative If x = y the answer is zero If x < y the answer is positive
The answer depends on the signs of the original intercepts.x negative, y negative: negative slope becomes less negative and could go positive.x negative, y positive: positive slope becomes greater.x positive, y negative: positive slope becomes less positive and could go negative.x positive, y positive: negative slope becomes more negative.For 1 and 3, the slope changes sign when the y intercept crosses the origin.
The top left quadrant is II (2) (x is negative, y is positive) The top right quadrant is I (1) (x is positive, y is positive) The bottom left quadrant is III (3) (x is negative, y is negative) The bottom right quadrant is IV (4) (x is positive, y is negative)
It is both because above the origin it is positive and below the origin it is negative
y is positive in quadrants I and II and negative in III and IV.
Positive minus a negative = positive plus a positive two negatives make a positive 3- (-1) = 3 + 1 = 4 5- (-7) = 12
Quadrant I: x positive, y positive. Quadrant II: x negative, y positive. Quadrant III: x negative, y negative. Quadrant II: x positive, y negative.
Suppose x and y are two POSITIVE numbers so that -x and -y are negative. Then a negative minus a negative = (-x) - (-y) = -x +y If x > y the answer is negative If x = y the answer is zero If x < y the answer is positive
A negative minus a negative turns the latter into a plus positive,for example -6 minus -3 would be :-6 ++ 3 = -3A minus negative always turns into a plus positive...To get more Specific:Suppose x and y are two POSITIVE numbers so that -x and -y are negative. Then a negative minus a negative = (-x) - (-y) = -x +yIf x > y the answer is negativeIf x = y the answer is zeroIf x < y the answer is positive
No, the y-coordinate can be positive or negative.
The answer depends on the signs of the original intercepts.x negative, y negative: negative slope becomes less negative and could go positive.x negative, y positive: positive slope becomes greater.x positive, y negative: positive slope becomes less positive and could go negative.x positive, y positive: negative slope becomes more negative.For 1 and 3, the slope changes sign when the y intercept crosses the origin.
Quadrant I: Top Right: x positive, y positive Quadrant II: Top Left: x negative, y positive Quadrant III: Bottom Left: x negative, y negative Quadrant IV: Bottom Right: x positive, y negative
The difference between a positive integer and a negative integer is ALWAYS positive.Suppose X and Y are positive so that -Y is negative,The the difference two numbers, A and B is A - B so the difference between X and (-Y) is X - (-Y) which equals X + Y. The sum of two positive numbers is always positive.
x - -y = x + y.
Quadrant.......... X ...........Y .......I ............positive..positive ......II............negative positive .....III............negative negative ......IV............positive...negative ---------------|--------------- ------Q2------|-------Q1----- ---------------|--------------- ---------------|--------------- ========|========= ---------------|--------------- ---------------|--------------- ------Q3------|------Q4------ ---------------|---------------
a negative + negative = negative (ex. -10+-10=-20) a positive + negative = a positive or a negative depending on how high the negative number is (ex1. 10+-5=5 , ex2. 10+-15=-5) a positive + positive = a positive "obviously" (ex. 2+2=4) a negative - negative = positive (ex. -5--10=5) because the minus sign and the negative sign automatically turn into an addition sign.
The top left quadrant is II (2) (x is negative, y is positive) The top right quadrant is I (1) (x is positive, y is positive) The bottom left quadrant is III (3) (x is negative, y is negative) The bottom right quadrant is IV (4) (x is positive, y is negative)