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If the variables are x1 & x2 the solution is : 1) x1=x1+x2; 2) x2=x1-x2; 3) x1=x1-x2; EX: x1=1 , x2=6; 1) x1= 1+6 = 7 2) x2= 7-6 =1 3 x1=7-1 =6 ============================================

integrate of x is 1/2x^2. integrate of 1 is x

Slope= Y2-Y1 over X2-X1.for example the slope of the points (2,2) & (1,0) m=y2-y1 over x2-x1 =0-2 over 1-2 =-2/-1 =2

sqr.rtx/x= sqrt.x*sqr.rtx/sqr.rtx=x/x*sqrt.x=1/sqrt.x. x1/2 = x1/2 * x1/2 = x = 1 (x1/2) /x= 1/x1/2

2

1 x1 = 13 x 6 = 18

Under the hood, in the fuse panel. There's probably a cover over it with a thumbscrew. The relay will probably be 1"x1" or 1"x1/2"

5/8 x1/20 = 1/32

X2 jumps over X1's lightsaber and X1 kills himself

no, its subtraction. if x2 is over x to the first power, the exponent at the higher value subtracts the x1. whether the x2 is above or below x1, x1 is always being subtrated from x2. X2 X(1) x __ OR __ = X or _ X(1) X2 1

You can integrate 1/2 and 1/2 and it will make a whole.

it equals x1 it equals x1

400.

4

The answer depends on absolute deviation from what: the mean, median or some other measure. Suppose you have n observations, x1, x2, ... xn and you wish to calculate the sum of the absolute deviation of these observations from some fixed number c. The deviation of x1 from c is (x1 - c). The absolute deviation of x1 from c is |x1 - c|. This is the non-negative value of (x1 - c). That is, if (x1 - c) â‰¤ 0 then |x1 - c| = (x1 - c) while if (x1 - c) < 0 then |(x1 - c)| = - (x1 - c). Then the sum of absolute deviations is the above values, summed over x1, x2, ... xn.

1"x1"

This is the same as 4x-1, so the answer is just 4 ln x + C.

Monsters: (22)Dark Magician x1Dark Magician Girl x1Gazelle the King of Mythical Beasts x1Berfomet x1King's Knight x1Queen's Knight x1Jack's Knight x1Mystical Elf x1Summoned Skull x1Archfiend of Gilfer x1Big Shield Guardna x1Black Luster Soldier Envoy of the Beginning x1Buster Blader x1Breaker the Magical Warrior x1Kuriboh x1Watapon x1Old Vindictive Magician x1Sangan x1Skilled Dark Magician x1Swift Gaia the Fierce Knight x1The Tricky x1Obnoxious Celtic Guardian x1Spells: (18)Card Destruction x1Exchange x1Change of Heart x1Dark Magic Curtain x1Dark Magician's Tome of Black MagicDiffusion Wave Motion x1Thousand Knives x1Pot of Greed x1Graceful Charity x1Multiply x1Fusion Gate x1Exchange x1Fiend's Sancturary x1Fissure x1Mystical Space Typhoon x1Swords of Revealing Light x1Monster Revorn x1Monster Reincarnation x1Magician's Unite x1Traps: (10)Chain Destruction x1Dust Tornado x1Lightforce Sword x1Magic Cylinder x1Meteorain x1Mirror Force x1Rope of Life x1Rope of Spirit x1Spellbinding Circle x1Regulation of Tribe x1Fusion: (3)Alkana Knight Joker x1Chimera the Flying Mythical Beast x1Dark Paladin x1

Aaron Poison/Bug x1 Bug/Fighting x1 Bug/Flying x2 Poison/Dark x1 Bertha Water/Ground x2 Ground x1 Rock x1 Rock/Ground x1 Flint Fire x1 Fire/Fighting x1 Steel/Ground x1 Normal x1 Ghost/Flying x1 Lucian Psychic x2 Normal/Psychic x1 Fight/Psychic x1 Steel/Psychic x1 Cynthia Ghost/Dark x1 Dragon/Ground x1 Water/Ground x1 Water x1 Grass/Poison x1 Steel/Fighting x1

1' x 1' x1'

2x

notation: natural numbers = 0,1, 2, 3, 4, 5, ....., (some define it without the zero, though) <= means smaller than or equal to, {} is set notation and means a set of numbers : (such that) then some condition. For example {x: x is not a duck} is the set of all things not a duck. Our goal is to prove that there are 21 different times. let x1 = hours, x2 = tens of minutes, x3 = minutes. We are going to prove the statement about the set {x1, x2,x3: 1<=x1 <= 12, 0<= x2<=5, 0<=x3 <= 59, x1 + x2 + x3 = 6}. It will be taken by assumption that this set is the set of digital clock combinations that add up to 6. So then, we must prove that there are unique 21 elements in the set {x1 + x2 + x3 : 1<= x1 <= 12, 0<= x2<=5, 0<=x3 <= 59, x1 + x2 + x3 = 6}. {x1 , x2 , x3 : 1<= x1 <= 12, 0<= x2<=5, 0<=x3 <= 59, x1 + x2 + x3 = 6} = {x1 , x2 , x3 : 1<= x1 <= 6, 0<= x2<=5, 0<=x3 <= 5, x1 + x2 + x3 = 6} because x3<=6, and because if x1 >=1, then x2 + x3 <=5, and x3, x2 >= 0 , so surely x3, x2 <= x5. Either x1 = 1, 2, 3, 4, 5, or 6. Next, x1 + x2 + x3 = 6, so x2 + x3 = 6 - x1. There are n+1 natural numbers between 0 and n (I'm being lazy and not proving this, but the proof would be so much longer if I proved it), and since 0 <= x2 <= 5 <= 6-x1, there are at most 6-x1+1 values of x2 for each value of x1. When x1 = 1, there are a maximum of 6, when x1 = 2, there are 6-2+1 = 5, when x1 = 3, there are 6-3+1 = 4, when x1 = 3, there are 3, then 2, and then 1. Summing this up gives us a maximum of 21. So it is at most 21 and at least 21, so exactly 21.

First of all, find the total number of not-necessarily distinguishable permutations. There are 12 letters in hippopotamus, so use 12! (12 factorial), which is equal to 12 x 11x 10 x9 x8 x7 x6 x5 x4 x3 x2 x1. 12! = 479001600.Then count the of each letter and calculate how many permutations of each letter can be made. For example, here is 1 h, so there is 1 permutation of 1 h.H 1I 1P 60 2T 1A 1M 1U 1S 1Multiply these numbers together. 1 x1 x6 x2 x1 x1 x1 x1 x1 = 12Divide 12! by this number. 479001600 / 12 = 39,916,800 Distinguishable Permutations.

Subtract them. example: x3 --- x1 Subtract the 1 from the 3 and you get x2 over 1 or just x2

monsters(19) 1.prime material dragon x2 2.the creator x2 3.cyber dragon x1 4.freed the brave wanderer x2 5.zaborg the thunder monarch x3 6.copycat x1 7.reflect bounder x1 8.skelengel x2 9.morphing jar x1 10.marshmallon x1 11.d.d. warrior lady x1 12.the creator incarnate x2 spelles(17) 1.card of safe return x3 2.heavy storm x1 3.monster reborn x1 4.reinforscment of the army x3 5.enemy controller x1 6.fissure x1 7.smashing ground x1 8.mystical space typhoon x1 9.foolish burrial x2 10.shrink x2 11.lightning vortex x1 12.monster reincarnation x1 traps(5) 1.solmen judgment x3 2.mirror force x1 3.torrential tribute x1