Q: How do you make 13 using four 4s?

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The answer is 4! - [(4+4)/4]

4! - 44/4 = 24 - 11 = 13

if you want to make eleven using only four 4s, this is the answer 4/.4+4/4(=10 + 1= 11) TA DA !

4+4+4x4 by the power of 0.

how do i make 17 using only 2 4 6 8

4/.4 + 4/4 [= 10+1 = 11]

4! - sqrt(4)*sqrt(4)/4 = 23

(44 - 4)/4

44-4/4

yrs

(4 * 4) - (4/4) equals 15.

4squared plus 4 minus 4/4= 19

4/4 + 4/4

4+4-(4/4)

44 divided by .44

One possible way: Make a 10 using five 4s as follows: 4 + 4 + (4 + 4)/4 = 10 Make another two 10s using five 4s in each. Multiply these three 10s.

4+4+(4-4) = 4

4 + 4 + 4/4 = 9

Google "Four Fours" and you will find a number of solutions, presented more comprehensively than we can.

4!/4 - 4/4 = 5

4!+(4+4!)/4

You can get 9 with the sum 4 + 4 + (4/4) = 9

_ (4/0.4)^sqrt4-4 =77 9 81 =77

4 ×(4 − 4 ÷ 4) or (44 + 4) ÷ 4

Three fours and one half of 4 Or if you mean using only fours and operation signs you develop methods like this: 42 - 4 + (4/4) = 13. In words, four squared (16) take 4 (12), + the sum of 4/4, which is one (13). Obviously, being an prime number, 13 doesn't fit equally into four, so use a combination of different mathematical symbols to change four into many other numbers: 42 = 16 Square Root of four = 2 4! (four factorial) = 24 43 = 64 4/4 = 1 4 + 4 = 8 Combinations of these can be used to make the 13 you're after.

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