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This is a simple algebra question:

d + n = 31

.1d + .05n = 2.65

Subsituting in for "d" using "n" we have:

d = 31 - n

3.1 - .1n + .05n = 2.65

-0.05n = -0.45

Solve for n:

n = 9

d + 9 = 31

d = 22

Thus, there are 9 nickels and 22 dimes.

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โˆ™ 2010-01-11 03:48:10
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Q: How do you make 2.65 out of dimes and nickels only using thirty-one coins?
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