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Q: How do you make 24 with the numbers 2 8 3 9?

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2+3+7+9+3=24

[3 - 2 - (-5)] * -(-4) = 24

5x2=10-2=8x3=24

3 x 23= 3 x 8 = 24

2 x 2 x 2 x 3 = 24

Assuming the order is unimportant (as this was not stipulated) then either: ((5*2) - 2) * 3 = 24 or 52 - (3-2) = 24.

1, 2 and 21 when added.

1*2*3*4=24

2 and 3 2*2*2*3 = 24 or 23*3 = 24

One possibility is :- 52 - (3 - 2) = 25 - 1 = 24 Another is :- 22 + 5 - 3 = 24 also 25 + 2 - 3 = 24

Yes. 6*(5 - 3)*2 = 6*2*2 = 12*2 = 24

5! / 4 - 2 * 3

2 and 3 (24 = 2*2*2*3).

24 = 2 × 2 × 2 × 3

21+3 or using all the numbers: 21 + (3*(2-1))

1, 2, 3, 4, 6, 8, 12, 24.

2*2-*2*3 = 24 or as 23*3 = 24

Prime factorization is where you take a number like 24 and make it into the prime numbers that multuply to make it. like this 24 / \ 4 6 / \ / \ 2 2 2 3 The prime factorization of 24 is 2 x 2 x 2 x 3, or 2 cubed times 3. All you have to do is make the factor tree and think of two numbers that, multuplied, make the number before it until it's all prime numbers like I did.

4! * 2 + 1 - 3 =24*2 + 1 - 3 = 48 + 1 - 3 = 46

(3*3-6)*8=24

By using: (3*6)+(3*2) = 24

106------------------------------------------------------------------------------------------------From Rafaelrz.You can make, 4P3 = 4!/(4-3)! = 24, different 3 digit numbers using 1, 2, 3 and 4.

(8 + 4)*(3 - 1) = 12 * 2 = 24 is one way.

9+3+(-2*-6) = 24

(1+7)*(9-2-4) = 8*3 = 24 Simple!