one way to make 60 ce
nts is to have 2 pieces -$0.25 a
nd 1 piece $0.10
10- 1 cent 14 - 5 cents 2- 10 cents
1 dime and 5 pennies
How do you get 67 cents wit 5 coins
10 pennies and 8 nickels =18 coins 10 cents + 40 cents = 50 cents
001 of a cent = 1 cent and you will need 100 of them to make a dollar.
10- 1 cent 14 - 5 cents 2- 10 cents
The answer to the question as written is no. The smallest number would be 4 coins: 1 quarter, 4 dimesHowever the question isn't correctly written. It's a actually brain teaser that asks, "Can you make 55 cents using two coins if one of them is not a nickel?" The answer of course is a half dollar and a nickel - the half dollar is the coin that's not a nickel!
Quarter, half-dollar, and nickel
four dimes equal 40 cents ten nickels equal fifty cents ten pennies equal 10 cents Add the 3 groups of coins for one dollar
A half dollar and five pennies
A half dollar and a nickel. One of them isn't a nickel, the other one is.
A half dollar (50-cent piece), 7 nickels, and a penny.
That's a trick question that usually goes, "one of them isn't a nickel." The answer is a half dollar and a nickel. One of them isn't a nickel, the other one is.
65/5= 13 nickels
1 dime and 5 pennies
How do you get 67 cents wit 5 coins
I don't think that this can be done using current US coins. In Canada, however, there are at least three combinations: -- 80 cents, 17 dimes, 2 quarters and a two-dollar coin -- 85 cents, 9 dimes, 5 quarters and a two-dollar coin -- 90 cents 1 dime, 8 quarters and a two dollar coin