360
180,2
90,2,2
45,2,2,2
15,3,2,2,2
5,3,3,2,2,2
390
195,2
65,3,2
13,5,3,2
293 is prime. No tree.
39 3,13
69 3,23
83 is prime. No tree.
61 is already prime. It doesn't need a tree.
You don't. 41 is a prime number. Prime numbers don't have factor trees, since they only have one prime factor.
it's prime
There is no factorization of 293 because 293 is a prime number. It is divisible only by 1 and itself.
879 l / \ / \ 293 3
The factor pairs of 293 are 293 and 1. 293 is prime, so it has only one factor pair.
1, 293
293 is.
The factors of 293 are 1 and 293.
293 is already prime. No tree.
The factor tree is as follows: 114 57,2 19,3,2
no
It is itself because 293 is a prime number
You cannot really make a factor tree for 7 because it is already a prime number.