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To count the number of times a digit occurs in an integer, start by initializing an array of ten counts of digits, such as int digits[10];

Then, in a loop while the number is non zero, increment the element in the digits array that corresponds to the units digit, and then divide the number by ten, such as digits[number%10]++ and number/=10;

int digits[10];
int i;
int number = some number;

for (i=0; i<10; i++) digits[i]=0;
do (digits[number%10]++; number/=10) while (number != 0);

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Q: How do you make a program that counts how many times each digit occured in the integer?
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