x times y is "xy"
To multiply TWO polynomials, you multiply each term in the first, by each term in the second. This can be justified by a repeated application of the distributive law. Two multiply more than two polynomials, you multiply the first two. Then you multiply the result with the third polynomial. If there are any more, multiply the result with the fourth polynomial, etc. Actually the polynomials can be multiplied in any order; both the communitative and associate laws apply.
You just multiply the term to the polynomials and you combine lije terms
(x - (-3)) (x - (-5)) (x - 2), or(x + 3) (x + 5) (x - 2)You can multiply the binomials to get a polynomial of degree 3.
multiply by 2y/x
y is the result if you multiply x by 3 and add 5 to it. For example, if you claim that x is 1, then if you multiply x by 3 and add 5, you would get 8. This result, 8, is what y is equal to (when x equals 1).
no only the coefficients can. like rad 5 but not x or y
what is the prosses to multiply polynomials
The problem to solve is: xy+x+3y+3 Multiply y and x Multiply the y and x Multiply y and x The y just gets copied along. The x just gets copied along. The answer is yx yx x*y evaluates to yx x*y+x evaluates to yx+x Multiply y and 3 Multiply y and 1 The y just gets copied along. The answer is y y 3*y evaluates to 3y The answer is yx+x+3y x*y+x+3*y evaluates to yx+x+3y The answer is yx+x+3y+3 x*y+x+3*y+3 evaluates to yx+x+3y+3 ---- The final answer isyx+x+3y+3----
x as a percentage of y = x/y * 100% divide x by y then multiply by 100%
When you add polynomials, you combine only like terms together. For example, (x^3+x^2)+(2x^2+x)= x^3+(1+2)x^2+x=x^3+3x^2+x When you multiply polynomials, you multiply all pairs of terms together. (x^2+x)(x^3+x)=(x^2)(x^3)+(x^2)(x)+(x)(x^3)+(x)(x)=x^5+x^3+x^4+x^2 Basically, in addition you look at like terms to simplify. In multiplication, you multiply each term individually with every term on the opposite side, ignoring like terms.
To multiply TWO polynomials, you multiply each term in the first, by each term in the second. This can be justified by a repeated application of the distributive law. Two multiply more than two polynomials, you multiply the first two. Then you multiply the result with the third polynomial. If there are any more, multiply the result with the fourth polynomial, etc. Actually the polynomials can be multiplied in any order; both the communitative and associate laws apply.
You just multiply the term to the polynomials and you combine lije terms
(x - (-3)) (x - (-5)) (x - 2), or(x + 3) (x + 5) (x - 2)You can multiply the binomials to get a polynomial of degree 3.
multiply by 2y/x
Flip the second fraction upside down and multiply. For example, if you want to divide (a/b) by (x/y), multiply (a/b) by (y/x).
y is the result if you multiply x by 3 and add 5 to it. For example, if you claim that x is 1, then if you multiply x by 3 and add 5, you would get 8. This result, 8, is what y is equal to (when x equals 1).
If you only look at the value of the roots and not their multiplicity then the answer is yes.The straight line y = x - 1 and the parabola y = (x - 1)^2 have the same root: x = 1. But the graphs are obviously different. All polynomials of the form y = (x - 1)^n will have x = 1 as the only root but they will have different shapes. The reason to this is that in the case of the straight line it is a root of multiplicity 1, in the case of a parabola it is a root of multiplicity 2 and in the case of y = (x - 1)^n it is a root of multiplicity n.