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just multiply. (think: distributive law) To get 18 gal 6 qt

Q: How do you perform 9 gal 3 qt x 2?

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That's 18 qt less 7 qt ie 11 qt = 2 gal 3 qt

14 gal 2 qt

3 gal, 2 qt

2 gal 10 qt

1 gallon = 4 quarts → 1 gal 1 qt - 3 qt = (4 qt + 1 qt) - 3 qt = 2 qt 2 qt = 2 ÷ 4 gal = 1/2 gal.

10gal 3 qt simplest form is 18 gal 2 qt

2 1/2 gal or 2.5 gal

4 qt = 1 gal8 qt = 2 gal12 qt = 3 gal

14 gal. 3 qt. doubled is 28 gal. 6 qt. which simplifies to 29 gal. 2 qt.

21 qt - 11 qt = 10 qt10 qt/4 qt= 2 gal 2 qtFirst convert the amounts into quarts. There are 4 quarts in every gallon. So, for the first amount: (5 x 4) + 1 = 21 qt. For the second amount: (2 x 4) + 3 = 11 qt. Then substitute these values for the ones you were originally going to subtract.So, since 5 gal 1 qt = 21 qt and 2 gas 3 qt = 11 qt, you'll have 21 qt - 11 qt, which equals 10 qt. You can then convert these 10 quarts to gallons. 10gal/4qt = 2 remainder 2; so: 2gal 2qt

6gals and 2 qts or 6 and 1 half gals

4:1 1:3 ---- 2:2 ----