700gram = 0.7 kilogram
By N1 V1 = N2 N2 1000 V1 = 100 * 100 V1= 100 * 100 / 1000 V1= 10 ml taken 10 ml from 1000 ppm and completed in 200 ml.
100 M HCl don't exist.
Mass of H2O2 = 0.637 g
1 l = 1000 ml ⇒ 100 l = 100 x 1000 ml = 100000 ml
Dissolve 128 mg of potassium bromate in 100 ml of deionised water
I will assume that you will start from the crystals of permanganate: Calculations: M.M. potassium permanganate: 158.04 g/mol mol KMnO4 in 10mL sol'n: 1.5 mol/L x 10 mL x (1 L / 1000 mL) = 0.015 mol grams potassium permanganate: 0.015 mol x 158.04 g/mol = 2.3706 g / 10 mL sol'n Preparation: 1. Weigh out analytically 2.3706g KMnO4 into a 10 mL volumetric flask. 2. Dilute to the mark with dH2O.
KMNO4 is ionic and so can be considered polar.
how much 95% alcohol must be used to prepare 1000 ml of 70% alcohol
Make a 1 to 100 dilution of the original 1000 ppm solution. That is take 1 ml and dilute to 100 ml, or take 10 ml and dilute to 1000 ml. This will give you a 10 ppm solution.
V = ( 100 cL ) ( 1 L/100 cL ) ( 1000 mL/L ) = 1000 mL = 1.00 L
0.1 liters is equal to 100 mL (1 liter = 1,000 mL).
1 litre = 1000 ml ⇒ 0.1 litre = 0.1 x 1000 ml = 100 ml