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What is 700 plus 80 plus N equals 780 plus N?
700 + 80 + n = 780 + n = 700 + 80 + n = 700 + 80 + n = 700 + 80 + n = 700 + 80 + n = 0 = 0
What is the answer in N divided by 80 equals 900?
If: N/80 = 900 Then: N = 72,000
What set of numbers has a mean of 80?
There are an infinite number of sets with mean 80. Here are some: {80, 80, 80}, {80, 80, 80, 80, 80, 80} {79, 80, 81}, {79, 79, 80, 81, 81}, {79, 79, 80, 82} (1, 80, 159}, {-40, 200} To produce a set of n numbers with mean 80, start with any set of n-1 numbers. Suppose their sum is S. Then add the number 80*n-S to the set. You will now have n numbers whose sum is S+80*n-S = 80*n So the mean of this set is 80.
If 58 percent equals 766 what does 80 percent equal?
58% : 766 = 80% : n 58%n/58% = (766 * 80%)/58% n = 1056.55
What is 10n equals 80?
10n = 80.n = 8.
How do you prepare and standardize of 0.1 N Sodium Thiosulfate solution?
Dissolve 2.48818g of Na2s2o3.5h2o in frishly boiled distilled water. and add 2ml of chloroform for stability, it gives 0.01N sodium thiosulphate sol.
How do you prepare 0.20mol of dc3 of sodium thiosulphate?
Dissolve 31,62 g anhydrous thiosulfate in 1 L demineralized water at 20 oC.
What is 700 plus 80 plus N equals 780 plus N?
700 + 80 + n = 780 + n = 700 + 80 + n = 700 + 80 + n = 700 + 80 + n = 700 + 80 + n = 0 = 0
Does the solution of thiosulphate reaction turn cloudy?
yes it does..... it also produces an odur which is sulphur from the thiosulphate.
What is the answer in N divided by 80 equals 900?
If: N/80 = 900 Then: N = 72,000
If 80 percent equals 500000 what does 100 percent equal?
100% is equal to 625000. 80% : 500000 = 100% : N 80%N/80%= (500000 * 100%)/80% N= 5000000/8 N= 625000
What set of numbers has a mean of 80?
There are an infinite number of sets with mean 80. Here are some: {80, 80, 80}, {80, 80, 80, 80, 80, 80} {79, 80, 81}, {79, 79, 80, 81, 81}, {79, 79, 80, 82} (1, 80, 159}, {-40, 200} To produce a set of n numbers with mean 80, start with any set of n-1 numbers. Suppose their sum is S. Then add the number 80*n-S to the set. You will now have n numbers whose sum is S+80*n-S = 80*n So the mean of this set is 80.
How do you prepare oxalic acid?
how do prepare 0.1 N Oxalic acid
Equation used to determine the iodine value?
Iodine value= (B-S)N x 12.69 ------------------- wt of sample where, B=titration of blank S= titration of sample N= normality of thiosulphate
Why is sodium thiosulphate used in iodometric titration?
· In analytical chemistry, sodium thiosulphate is used for the determination of the strength of a given solution of iodine. · Sodium thiosulphate is preferred in iodometric analysis due to the fact that sodium thiosulphate is oxidized by iodine. It is also used to determine the strength of many oxidizing agents.
What is the use of Sodium thiosulphate in iodometry?
In iodometry sodium thiosulphate is used because it is standardized by potassium dichromate and it is the best and relaible way to standardized sodium thiosulphate using iodometric titration. Infact sodium thiosulphate is also standardized by iodimetry. The difference between both of them is only of iodine. In iodometry iodine gas is liberated that will further react with sodium thiosulphate but in iodimetry standard solution of iodine is used.
If the product is 80 and the sum us 21 what are the numbers?
Let the number be 'm' & 'n' Hence Product ; mn = 80 Sum ; m + n = 21 m = 21 - n Substitute (21 - n) n = 80 21n - n^2 = 80 n^2 - 21 n + 80 = 0 It is now in quadratic form to factor. ( n - 16)(n - 5) = 0 Hence the numbers are 5 & 16
