5/(√3 - 1)
= 5(√3 + 1)/(√3 - 1)(√3 + 1)
= (5√3 + 5)/[(√3)2 - 12)
= (5√3 + 5)/(3 - 1)
= 5√3 + 5)/2
= 5√3/2 + 1/2
-26
Multiply everything by the square root of 3 minus the square root of 2 and then times that by 100 - 72 and divide that by 5
0.4
0.625
3.5714
-26
1.5
Multiply everything by the square root of 3 minus the square root of 2 and then times that by 100 - 72 and divide that by 5
6
0.4
0.625
The idea is to get rid of the square root in the denominator. For this purpose, you must multiply numerator and denominator by the square root of 6 in this case.
3.5714
Yes. For example, the conjugate of (square root of 2 + square root of 3) is (square root of 2 - square root of 3).
Multiplicative inverse is the number that, when multiplied, results in 1, usually 1/# 1/sqrt7 is the inverse, so just rationalize the denominator sqrt7/7 = square root of 7 divided by 7
Yes. The original denominator and its conjugate will form the factors of a Difference of Two Squares (DOTS) and that will rationalise the denominator but only if the radicals are SQUARE roots.
If you want to rationalize the denominator, then multiply numerator & denominator by sqrt(5), so 8*sqrt(5)/5 = approx 3.578