4
Unfortunately the question is too ambiguous. It could refer to any one of:
sqrt(x-2/sqrt(x) +2)
sqrt(x - 2)/sqrt(x + 2)
[sqrt(x) - 2]/[sqrt(x) + 2]
plus a whole load more. And each one has a different answer!
1.5
6
The idea is to get rid of the square root in the denominator. For this purpose, you must multiply numerator and denominator by the square root of 6 in this case.
8/sqrt(2) to get exact answer rationalize the denominator by this form of 1 sqrt(2)/sqrt(2) * 8/sqrt(2) = 8*sqrt(2)/2 or, the decimal answer = 5.656854249
In a way. You can multiply top and bottom by the square root of 2. This will not exactly make the expression simpler, but you'll get rid of the square root in the denominator (and transfer it to the numerator); this is considered to be the standard form for expressions which involve square roots. In other words, there should be no square roots in the denominator.
1.5
-26
Multiply everything by the square root of 3 minus the square root of 2 and then times that by 100 - 72 and divide that by 5
6
0.4
0.625
The idea is to get rid of the square root in the denominator. For this purpose, you must multiply numerator and denominator by the square root of 6 in this case.
3.5714
Yes. For example, the conjugate of (square root of 2 + square root of 3) is (square root of 2 - square root of 3).
Multiplicative inverse is the number that, when multiplied, results in 1, usually 1/# 1/sqrt7 is the inverse, so just rationalize the denominator sqrt7/7 = square root of 7 divided by 7
Yes. The original denominator and its conjugate will form the factors of a Difference of Two Squares (DOTS) and that will rationalise the denominator but only if the radicals are SQUARE roots.
If you want to rationalize the denominator, then multiply numerator & denominator by sqrt(5), so 8*sqrt(5)/5 = approx 3.578