There must be at least one nickel, to account for the 5 cents of the 75 cents.
So, one solution would be 1 nickel and 277 dimes.
This would be (277 x 0.10) + 0.05 = 27.70 + 0.05 = 27.75
Another solution would be 1 dime and 553 nickels.
This would be (553 x 0.05) + 0.10 = 27.65 + 0.10 = 27.75
You will have an odd number of nickels in an solution. Possible solutions include
1 nickel & 277 dimes
3 nickels & 276 dimes
5 nickels & 275 dimes
7 nickels & 274 dimes
9 nickels & 273 dimes
up to
553 nickels and 1 dime
There are 25 of them.
42 combinations.
2 dimes and 5 nickels
18
There are sixteen different ways.
The combinations depend on how many are dimes and how many nickels.
Anywhere from two nickels and 199 dimes to 398 nickels and one dime with a few hundred combinations in between.
5 of them.
Six.
729
There are 18 possible combinations of quarters, dimes and nickels that total 75 cents. They are: 1) -- 3 Quarters 2) -- 2 Quarters, 2 Dimes, 1 Nickel 3) -- 2 Quarters, 1 Dime, 3 Nickels 4) -- 2 Quarters, 5 Nickels 5) -- 1 Quarter, 5 Dimes 6) -- 1 Quarter, 4 Dimes, 2 Nickels 7) -- 1 Quarter, 3 Dimes, 4 Nickels 8) -- 1 Quarter, 2 Dimes, 6 Nickels 9) -- 1 Quarter, 1 Dime, 8 Nickels 10) -- 1 Quarter, 10 Nickels 11) -- 7 Dimes, 1 Nickel 12) -- 6 Dimes, 3 Nickels 13) -- 5 Dimes, 5 Nickels 14) -- 4 Dimes, 7 Nickels 15) -- 3 Dimes, 9 Nickels 16) -- 2 Dimes, 11 Nickels 17) -- 1 Dime, 13 Nickels 18) -- 15 Nickels
There are 12 different combinations using pennies, nickels and dimes. 25 pennies 20 pennies and 1 nickel 15 pennies and 2 nickels 15 pennies and 1 dime 10 pennies and 3 nickels 10 pennies 1 dime and 1 nickel 5 pennies and 4 nickels 5 pennies 1 dime and 2 nickels 5 pennies and 2 dimes 5 nickels 1 dime and 3 nickels 2 dimes and 1 nickel