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Q: How do you simplify square root of 72 and square root of 2?

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The square root of 72 is equivalent to 6 times the square root of 2.

6 root(2) = root(36) root(2) = root(36 x 2) = root(72).

The square root of 4 = 2

2 times the square root of 165

2 times the square root of 35

6(square root of)3

sqr root of 18 = 3 * square root of 2

36

2

36

98 is 49 times 2 so the square root of 98 is the square root of 49 times the square root of 2. But the square root of 49 is 7 , so the answer is 7 times the square root of 2.

It is: 2 times the square root of 21 and it's an irrational number

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The square root of 60 is also equal to the square root of 15x4 the square root of 4 is 2, and 15 is not a perfect square, so the answer is (square root of 15) x 2

It might be best to answer this with an example. Look at the square root of 8. To simplify it we notice that 8 is 2x4 and that 4 is a perfect square. So we can simplify the square root by taking the 4 out of the radical sign and writing it as 2xsquare root of 2. Perhaps a better way to think of this is that is you have square root of a x square root of b, that is the square root of (ab). So if we have square root of 8 that is the same as square root of 4 x square root of 2 and square root of 4 is 2 so the answer is 2xsquare root of 2. In general, look for perfect squares and factor them out of the number so they can be removed from the square root.

6 root 2 or 8.485281374

0.0278

To simplify the square root of 12: Look at numbers that can be reduced from the larger number and can be square rooted itself. 4 * 3 = 12 The square root of 4 is 2. Therefore the simplification of the square root of 12 is: 2*square root of 3

50 = 2 x 25 so root 50 = root 25 x root 2 = 5 root 2

First you do the square root, then the multiplication, then the addition.

2 square root of 5

6

sqrt(72) = sqrt(36*2) = sqrt(36)*sqrt(2) = 6*sqrt(2).

Multiply everything by the square root of 3 minus the square root of 2 and then times that by 100 - 72 and divide that by 5

No, it cannot be simplified.