i is equal to the square root of negative one
3 * square root of negative one times -4 * square root of negative one
totally simplified it is 2i√(3)
3i times -4i equals -12 times i squared. i squared equal -1, so -12 times -1 equals 12.
- - x + 3 = x + 3
(x - 4i)(x + 4i) where i is the square root of -1
As an algebraic expression it is simply: 18-x
Without further information, it is not possible to evaluate or simplify the expression.
3x+3-2x=3 x+3=3 x-0
(3-4i)(1-i) = (3x1) + (3 x -i) + (-4i x 1) + ( -4i x -i) = 3 - 3i -4i -4 = -1 - 7i
The value of the expression x2 + 9 will depend on what value you plug in for x. If you are looking to factor that expression, it can only be done using complex numbers:x2 + 9 = (x + 3i)(x - 3i)
- - x + 3 = x + 3
(x - 4i)(x + 4i) where i is the square root of -1
As an algebraic expression it is simply: 18-x
x^2 + 3 = x^2 - (-3) = x^2 - 3i^2 = (x - i√3)(x + i√3)
x2 + 9 has no real factors. Its complex factors are (x + 3i) and (x - 3i) where i is the imaginary square root of -1.
x-(x+4)
3x2 + 51 = 6x Rewrite the equation so that it equates to zero 3x2 - 6x + 51 = 0 Simplify by dividing by 3 x2 - 2x + 17 = 0 Then use the quadratic formula x = {2 ± √[(-2)2 -(4x1x17)]} ÷ 2 = { 2 ± √-64} ÷ 2 = 1 ± 4i Then x = 1 + 4i and x = 1- 4i
32
3x2 = -9 (divide both sides by 3) x2 = -3 (x would have to be the square root of -3) x = ±√-3 x = ±√3i Since you want to solve by factoring: x2 = -3 add 3 to both sides x2 + 3 = 0 x2 - 3i2 = 0 x2 - (√3i)2 = 0 Factor: (x - √3i)(x + √3i) = 0 x - √3i = 0 or x + √3i = 0 x = √3i or x = -√3i
Without further information, it is not possible to evaluate or simplify the expression.