Q: How do you simplify the square root of 16 plus 9?

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factor the perfect square simplify the perfect root factor out the perfect cube simplify the perfect root √32 = √16 = √8◦2 = 4√2 move 8 out and simplify it to a perfect square

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square root of 36 plus 10=6+10 , since square root of 36 =6=16Answer : 16

It is: 4+7 = 11

-- Recognize that 48 is the same as 16 x 3 . -- Substitute 16 x 3 in place of 48 . -- Take the square root of 16 and move it out of the square root, to multiply the 3 .

square root of 80 simplified= 16*5= 4 squared *5

I would say 19 as the square root of 9 is 3, plus 16, makes 19. I would assume the questioner expects many people to answer 5 which is the square root of the sum of 9 and 16.

Are you familiar with the concept of the square root of -1?This is represented by iFor the square root of 243 we can get i involved and say wer are looking for the square root ot [256 - 13(i2)]This can be simplified to [+/-16 - √13(i)]

The square root of 70 can not be simplified, because the number 70 is not divisible by any perfect square (4, 9, 16, 25, 36, 49).

It is 16 +/- 12*sqrt(3)*i where i is the imaginary square root of -1

âˆš (16t) =âˆš 16*âˆš t = 4*âˆš t

The square root of -16 is: 4 i

The square root of -16 is 4 i

sqrt(160) = sqrt(16*10) = sqrt(16)*sqrt(10) = 4*sqrt(10)

41

(sqrt(9) - sqrt(12) + sqrt(16)) x sqrt(2) = -2 sqrt(6) + 7 sqrt(2)

sqrt(16 + 9) = sqrt(25) = 5

The square root of 16 is 4.

Square root of 25 = +or- 5 Square root of -36 = +or- 6i where i is the imaginary number such that i^2=-1 Square root of 121 = +or-11 So the 8 possible answers are: -16-6i, -16+6i, -6-6i, -6+6i, 6-6i, 6+6i, 16-6i and 16+6i

16 or -16The square root of 256 is 16. 16

The idea is to take out perfect squares. The largest perfect square in this case is 256, which is the square of 16 (if you have trouble figuring this out, you can take out a smaller perfect square first, and then see if you find additional perfect squares). In any case, the end result should not have a factor that is a perfect square. Using the symbol "root()" for square root: root(512) = root(256 x 2) = root(256) x root(2) = 16 root(2)

The square root OF 16? It's 4.

Look for the largest square number in its factors. The square root of 512 is equal to the square root of 2 times the square root of 256. The square root of 256 is 16. The square root of 512 simplifies to 16 times the square root of 2.

This doesn't simplify unless you use the quadratic equation. If using the quadratic, the answer is 16 + -Ö 69 /5 In words, sixteen plus or minus the square root of sixty-nine divided by five