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Q: How do you solve 19a 2a-4a 3a?

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3a squared plus nine = 19a. 3a to the second power = 9a plus 9 = 19a.

a-1<2a-6<9+3a

3a x 2a =24

p=b+3a+c p-3a-c=b+3a-3a+c-c p-3a-c=b b=p-3a-c

-21 = 9a - 15 - 3a -6 = 6a -1 = a

(6a3 - 19a2 + 15a)/(2a - 3) = a(6a2 - 19a + 15)/(2a - 3) = a(2a - 3)(3a -5)/(2a -3) = a(3a - 5)

3.5

3a is part of an algebra equation. It mean the variable "a" time 3. to solve, you need to know the value of a. if the value of a is 5 the 3a would be 3 x 5 which is 15.

3a + 4 = 4a - 3 4 = a -3 (subtract 3a from each side) 7 = a (add 3 to both sides) a = 7

depends what 'a' =

36 -20 = 16

What is the answers to -7 ( a + b - 5 ) + 8 ( -3a +2b ) + b ( 7 + 3 )

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